9x^2+9x=270

Solution for 9x^2+9x=270 equation:

9x^2+9x=270

We move all terms to the left:

9x^2+9x-(270)=0

a = 9; b = 9; c = -270;
Δ = b2-4ac
Δ = 92-4·9·(-270)
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-99}{2*9}=\frac{-108}{18}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+99}{2*9}=\frac{90}{18}
=5
$